What are the solutions to the equation 7x^2-9x-10=0 ?

The solutions to the equation 7x^2-9x-10=0 are x=2,x=-5/7

Find the zeros of 7x^2-9x-10=0

The zeros of 7x^2-9x-10=0 are x=2,x=-5/7

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7 x^{2} - 9 x - 10 = 0

x = 2, x = - \frac{5}{7}

Decimal Notation

x = 2, x = - 0.71428 \dots

Solution steps

7 x^{2} - 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 7 ( - 10 )}{2 \cdot 7}

(- 9)^{2} - 4 \cdot 7 (- 10) = 19

x_{1, 2} = \frac{- ( - 9 ) \pm 19}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 19}{2 \cdot 7}, x_{2} = \frac{- ( - 9 ) - 19}{2 \cdot 7}

x = \frac{- ( - 9 ) + 19}{2 \cdot 7} : 2

x = \frac{- ( - 9 ) - 19}{2 \cdot 7} : - \frac{5}{7}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{7}

2 x^{2} - 6 x

p, pq x^{2} + (p^{2} - q^{2}) x = pq

12 x^{2} - 224 x + 703 = 0

a, (a + b)^{2} = 81

4 = (x + 2)^{2}

What are the solutions to the equation 7x^2-9x-10=0 ?
The solutions to the equation 7x^2-9x-10=0 are x=2,x=-5/7
Find the zeros of 7x^2-9x-10=0
The zeros of 7x^2-9x-10=0 are x=2,x=-5/7