What are the solutions to the equation (2x+1)(2x-1)=0 ?

The solutions to the equation (2x+1)(2x-1)=0 are x=-1/2 ,x= 1/2

Find the zeros of (2x+1)(2x-1)=0

The zeros of (2x+1)(2x-1)=0 are x=-1/2 ,x= 1/2

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(2 x + 1) (2 x - 1) = 0

x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = - 0.5, x = 0.5

Solution steps

(2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 2 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{1}{2}

1 2^{2} + 1 5^{2} = x^{2}

(3 x - 2)^{2} = 12

x^{2} - 1 x - 1 = 0

(m + 1) x^{2} - 2 x + 2 (m - 1) = 0

x^{2} - 8 x - 5

What are the solutions to the equation (2x+1)(2x-1)=0 ?
The solutions to the equation (2x+1)(2x-1)=0 are x=-1/2 ,x= 1/2
Find the zeros of (2x+1)(2x-1)=0
The zeros of (2x+1)(2x-1)=0 are x=-1/2 ,x= 1/2