What are the solutions to the equation 12^2+15^2=x^2 ?

The solutions to the equation 12^2+15^2=x^2 are x=3sqrt(41),x=-3sqrt(41)

Find the zeros of 12^2+15^2=x^2

The zeros of 12^2+15^2=x^2 are x=3sqrt(41),x=-3sqrt(41)

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1 2^{2} + 1 5^{2} = x^{2}

x = 341, x = - 341

Decimal Notation

x = 19.20937 \dots, x = - 19.20937 \dots

Solution steps

1 2^{2} + 1 5^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 1 5^{2}

Simplify

1 2^{2} + 1 5^{2} : 369

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 369, x = - 369

369 = 341

- 369 = - 341

x = 341, x = - 341

(3 x - 2)^{2} = 12

x^{2} - 1 x - 1 = 0

(m + 1) x^{2} - 2 x + 2 (m - 1) = 0

x^{2} - 8 x - 5

x^{2} - 8 x - 2

What are the solutions to the equation 12^2+15^2=x^2 ?
The solutions to the equation 12^2+15^2=x^2 are x=3sqrt(41),x=-3sqrt(41)
Find the zeros of 12^2+15^2=x^2
The zeros of 12^2+15^2=x^2 are x=3sqrt(41),x=-3sqrt(41)