What are the solutions to the equation x^2+8x-14=9 ?

The solutions to the equation x^2+8x-14=9 are x=-4+sqrt(39),x=-4-sqrt(39)

Find the zeros of x^2+8x-14=9

The zeros of x^2+8x-14=9 are x=-4+sqrt(39),x=-4-sqrt(39)

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x^{2} + 8 x - 14 = 9

x = - 4 + 39, x = - 4 - 39

Decimal Notation

x = 2.24499 \dots, x = - 10.24499 \dots

Solution steps

x^{2} + 8 x - 14 = 9

Move

9

to the left side

x^{2} + 8 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 23) = 239

x_{1, 2} = \frac{- 8 \pm 2 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 39}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 39}{2 \cdot 1}

x = \frac{- 8 + 2 39}{2 \cdot 1} : - 4 + 39

x = \frac{- 8 - 2 39}{2 \cdot 1} : - 4 - 39

The solutions to the quadratic equation are:

x = - 4 + 39, x = - 4 - 39

(a - 5)^{2} + 4 = 24

x (4 x - 7) = 0

2 y^{2} + 4 y

x, 4 x^{2} + 3 x y - y^{2} - 10 x - 3 y + 5 = 0

(m + 3) x^{2} - 2 m x + 4 = 0

What are the solutions to the equation x^2+8x-14=9 ?
The solutions to the equation x^2+8x-14=9 are x=-4+sqrt(39),x=-4-sqrt(39)
Find the zeros of x^2+8x-14=9
The zeros of x^2+8x-14=9 are x=-4+sqrt(39),x=-4-sqrt(39)