What are the solutions to the equation (a-5)^2+4=24 ?

The solutions to the equation (a-5)^2+4=24 are a=2sqrt(5)+5,a=-2sqrt(5)+5

Find the zeros of (a-5)^2+4=24

The zeros of (a-5)^2+4=24 are a=2sqrt(5)+5,a=-2sqrt(5)+5

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(a - 5)^{2} + 4 = 24

a = 25 + 5, a = - 25 + 5

Decimal Notation

a = 9.47213 \dots, a = 0.52786 \dots

Solution steps

(a - 5)^{2} + 4 = 24

Move

4

to the right side

(a - 5)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a - 5 = 20 : a = 25 + 5

Solve

a - 5 = - 20 : a = - 25 + 5

The solutions to the quadratic equation are:

a = 25 + 5, a = - 25 + 5

x (4 x - 7) = 0

2 y^{2} + 4 y

x, 4 x^{2} + 3 x y - y^{2} - 10 x - 3 y + 5 = 0

(m + 3) x^{2} - 2 m x + 4 = 0

3 x^{2} + 3 x - 10 = 0

What are the solutions to the equation (a-5)^2+4=24 ?
The solutions to the equation (a-5)^2+4=24 are a=2sqrt(5)+5,a=-2sqrt(5)+5
Find the zeros of (a-5)^2+4=24
The zeros of (a-5)^2+4=24 are a=2sqrt(5)+5,a=-2sqrt(5)+5