What are the solutions to the equation (x+5)(2x-3)=0 ?

The solutions to the equation (x+5)(2x-3)=0 are x=-5,x= 3/2

Find the zeros of (x+5)(2x-3)=0

The zeros of (x+5)(2x-3)=0 are x=-5,x= 3/2

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(x + 5) (2 x - 3) = 0

x = - 5, x = \frac{3}{2}

Decimal Notation

x = - 5, x = 1.5

Solution steps

(x + 5) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or 2 x - 3 = 0

Solve

x + 5 = 0 : x = - 5

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = - 5, x = \frac{3}{2}

6 x^{2} + 4 x - 32 = 0

x^{2} - 18 x - 144 = 0

3 x^{2} - 6 x + 0 = 0

x, z = x^{2} + x y + y^{2}

18 = 6 x + x (x - 13)

What are the solutions to the equation (x+5)(2x-3)=0 ?
The solutions to the equation (x+5)(2x-3)=0 are x=-5,x= 3/2
Find the zeros of (x+5)(2x-3)=0
The zeros of (x+5)(2x-3)=0 are x=-5,x= 3/2