What are the solutions to the equation quadraticformula 18=6x+x(x-13) ?

The solutions to the equation quadraticformula 18=6x+x(x-13) are x=9,x=-2

Find the zeros of quadraticformula 18=6x+x(x-13)

The zeros of quadraticformula 18=6x+x(x-13) are x=9,x=-2

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18 = 6 x + x (x - 13)

x = 9, x = - 2

Solution steps

18 = 6 x + x (x - 13)

Expand

6 x + x (x - 13) : x^{2} - 7 x

18 = x^{2} - 7 x

Switch sides

x^{2} - 7 x = 18

Move

18

to the left side

x^{2} - 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

x = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

x = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 9, x = - 2

y, 9 y^{2} = x (x - 3)^{2}

(4 x - 1) (2 x + 2) = 12

x^{2} + 3 x + 3

x^{2} + 3 x - 4

- x^{2} + 10 x - 23 = 0

What are the solutions to the equation quadraticformula 18=6x+x(x-13) ?
The solutions to the equation quadraticformula 18=6x+x(x-13) are x=9,x=-2
Find the zeros of quadraticformula 18=6x+x(x-13)
The zeros of quadraticformula 18=6x+x(x-13) are x=9,x=-2