What are the solutions to the equation (2m-1)^2-4=14 ?

The solutions to the equation (2m-1)^2-4=14 are m=(3sqrt(2)+1)/2 ,m=(-3sqrt(2)+1)/2

Find the zeros of (2m-1)^2-4=14

The zeros of (2m-1)^2-4=14 are m=(3sqrt(2)+1)/2 ,m=(-3sqrt(2)+1)/2

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(2 m - 1)^{2} - 4 = 14

m = \frac{3 2 + 1}{2}, m = \frac{- 3 2 + 1}{2}

Decimal Notation

m = 2.62132 \dots, m = - 1.62132 \dots

Solution steps

(2 m - 1)^{2} - 4 = 14

Move

4

to the right side

(2 m - 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 m - 1 = 18 : m = \frac{3 2 + 1}{2}

Solve

2 m - 1 = - 18 : m = \frac{- 3 2 + 1}{2}

The solutions to the quadratic equation are:

m = \frac{3 2 + 1}{2}, m = \frac{- 3 2 + 1}{2}

(x + 6) (x + 5) = 2

8 y^{2} - 7 = 193

n^{2} - 18 = - 3 n

2 n^{2} + 5 n - 9 = 0

x^{2} + \frac{5}{12} x - \frac{1}{6} = 0

What are the solutions to the equation (2m-1)^2-4=14 ?
The solutions to the equation (2m-1)^2-4=14 are m=(3sqrt(2)+1)/2 ,m=(-3sqrt(2)+1)/2
Find the zeros of (2m-1)^2-4=14
The zeros of (2m-1)^2-4=14 are m=(3sqrt(2)+1)/2 ,m=(-3sqrt(2)+1)/2