What are the solutions to the equation n^2-18=-3n ?

The solutions to the equation n^2-18=-3n are n=3,n=-6

Find the zeros of n^2-18=-3n

The zeros of n^2-18=-3n are n=3,n=-6

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n^{2} - 18 = - 3 n

n = 3, n = - 6

Solution steps

n^{2} - 18 = - 3 n

Move

3 n

to the left side

n^{2} - 18 + 3 n = 0

Write in the standard form

a x^{2} + b x + c = 0

n^{2} + 3 n - 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

n_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 9}{2 \cdot 1}, n_{2} = \frac{- 3 - 9}{2 \cdot 1}

n = \frac{- 3 + 9}{2 \cdot 1} : 3

n = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 3, n = - 6

2 n^{2} + 5 n - 9 = 0

x^{2} + \frac{5}{12} x - \frac{1}{6} = 0

(x + 5) (x - 6) = - 26

x, 5 x^{2} - 6 x y + 5 y^{2} = 4

- 4 x^{2} + 2 x + 2 = 0

What are the solutions to the equation n^2-18=-3n ?
The solutions to the equation n^2-18=-3n are n=3,n=-6
Find the zeros of n^2-18=-3n
The zeros of n^2-18=-3n are n=3,n=-6