What are the solutions to the equation 2x^2+8x=24 ?

The solutions to the equation 2x^2+8x=24 are x=2,x=-6

Find the zeros of 2x^2+8x=24

The zeros of 2x^2+8x=24 are x=2,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 8 x = 24

x = 2, x = - 6

Solution steps

2 x^{2} + 8 x = 24

Move

24

to the left side

2 x^{2} + 8 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 24) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 2}, x_{2} = \frac{- 8 - 16}{2 \cdot 2}

x = \frac{- 8 + 16}{2 \cdot 2} : 2

x = \frac{- 8 - 16}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

x^{2} + 8 x - 35 = 0

8 x^{2} + 157 x - 60 = 0

3 x - 2 = x^{2}

2 x^{2} + 3 = 9

x^{2} + 8 x - 33 = 9

What are the solutions to the equation 2x^2+8x=24 ?
The solutions to the equation 2x^2+8x=24 are x=2,x=-6
Find the zeros of 2x^2+8x=24
The zeros of 2x^2+8x=24 are x=2,x=-6