What are the solutions to the equation 7^2+11^2=c^2 ?

The solutions to the equation 7^2+11^2=c^2 are c=sqrt(170),c=-sqrt(170)

Find the zeros of 7^2+11^2=c^2

The zeros of 7^2+11^2=c^2 are c=sqrt(170),c=-sqrt(170)

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7^{2} + 1 1^{2} = c^{2}

c = 170, c = - 170

Decimal Notation

c = 13.03840 \dots, c = - 13.03840 \dots

Solution steps

7^{2} + 1 1^{2} = c^{2}

Switch sides

c^{2} = 7^{2} + 1 1^{2}

Simplify

7^{2} + 1 1^{2} : 170

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 170, c = - 170

(x - 6) (x + 1) = 0

y, (x + y)^{2} + (x - y)^{2} = x^{3} + y^{2}

x^{2} + 5 x + 15 = 0

7 n^{2} + 9 n + 2 = 0

(x + 2)^{2} - 5 = 19

What are the solutions to the equation 7^2+11^2=c^2 ?
The solutions to the equation 7^2+11^2=c^2 are c=sqrt(170),c=-sqrt(170)
Find the zeros of 7^2+11^2=c^2
The zeros of 7^2+11^2=c^2 are c=sqrt(170),c=-sqrt(170)