What are the solutions to the equation p^2-12p=0 ?

The solutions to the equation p^2-12p=0 are p=12,p=0

Find the zeros of p^2-12p=0

The zeros of p^2-12p=0 are p=12,p=0

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p^{2} - 12 p = 0

p = 12, p = 0

Solution steps

p^{2} - 12 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 0 = 12

p_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 1}, p_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 1}

p = \frac{- ( - 12 ) + 12}{2 \cdot 1} : 12

p = \frac{- ( - 12 ) - 12}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 12, p = 0

2 t^{2} - 3 t - 1 = 0

(x - 2) (x + 5) = 3

x^{2} - 21 x - 72 = 0

81 x^{2} - 18 x + 1 = 0

6 (x^{2} - 1) = 3 (x^{2} + x) - 1

What are the solutions to the equation p^2-12p=0 ?
The solutions to the equation p^2-12p=0 are p=12,p=0
Find the zeros of p^2-12p=0
The zeros of p^2-12p=0 are p=12,p=0