What are the solutions to the equation u^2+4u+4=0 ?

The solutions to the equation u^2+4u+4=0 are u=-2

Find the zeros of u^2+4u+4=0

The zeros of u^2+4u+4=0 are u=-2

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u^{2} + 4 u + 4 = 0

u = - 2

Solution steps

u^{2} + 4 u + 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

u_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

u = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

u = - 2

The solution to the quadratic equation is:

u = - 2

y, x^{2} + (y + \frac{3}{4})^{2} = 1

4 p^{2} + 23 = 7

x^{2} = 0.1

b, N b^{2} - r = 3 T

x^{2} = 17 x

What are the solutions to the equation u^2+4u+4=0 ?
The solutions to the equation u^2+4u+4=0 are u=-2
Find the zeros of u^2+4u+4=0
The zeros of u^2+4u+4=0 are u=-2