What are the solutions to the equation 0=3x^2+6x+3 ?

The solutions to the equation 0=3x^2+6x+3 are x=-1

Find the zeros of 0=3x^2+6x+3

The zeros of 0=3x^2+6x+3 are x=-1

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0 = 3 x^{2} + 6 x + 3

x = - 1

Solution steps

0 = 3 x^{2} + 6 x + 3

Switch sides

3 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

x = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

5 x^{2} + 10 x - 8 = 0

4 k (k + 13) = 13

7 x^{2} + x = 0

x^{2} + 22 x + 40 = 0

2 x^{2} + 12 x - 6 = 0

What are the solutions to the equation 0=3x^2+6x+3 ?
The solutions to the equation 0=3x^2+6x+3 are x=-1
Find the zeros of 0=3x^2+6x+3
The zeros of 0=3x^2+6x+3 are x=-1