What are the solutions to the equation 3x^2=-6-8x ?

The solutions to the equation 3x^2=-6-8x are x=-4/3+i(sqrt(2))/3 ,x=-4/3-i(sqrt(2))/3

Find the zeros of 3x^2=-6-8x

The zeros of 3x^2=-6-8x are x=-4/3+i(sqrt(2))/3 ,x=-4/3-i(sqrt(2))/3

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3 x^{2} = - 6 - 8 x

x = - \frac{4}{3} + i \frac{2}{3}, x = - \frac{4}{3} - i \frac{2}{3}

Solution steps

3 x^{2} = - 6 - 8 x

Move

8 x

to the left side

3 x^{2} + 8 x = - 6

Move

6

to the left side

3 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

Simplify

8^{2} - 4 \cdot 3 \cdot 6 : 22 i

x_{1, 2} = \frac{- 8 \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- 8 - 2 2 i}{2 \cdot 3}

x = \frac{- 8 + 2 2 i}{2 \cdot 3} : - \frac{4}{3} + i \frac{2}{3}

x = \frac{- 8 - 2 2 i}{2 \cdot 3} : - \frac{4}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3} + i \frac{2}{3}, x = - \frac{4}{3} - i \frac{2}{3}

11 x^{2} + 5 = 49

a, (a + b)^{2} = 49 + 12 b

h^{2} + 5 h = 155

h^{2} - 7 h = 0

y, z = y^{2} + \frac{x ^{3}}{3} + x y

What are the solutions to the equation 3x^2=-6-8x ?
The solutions to the equation 3x^2=-6-8x are x=-4/3+i(sqrt(2))/3 ,x=-4/3-i(sqrt(2))/3
Find the zeros of 3x^2=-6-8x
The zeros of 3x^2=-6-8x are x=-4/3+i(sqrt(2))/3 ,x=-4/3-i(sqrt(2))/3