What are the solutions to the equation h^2+5h=155 ?

The solutions to the equation h^2+5h=155 are h=(-5+sqrt(645))/2 ,h=(-5-sqrt(645))/2

Find the zeros of h^2+5h=155

The zeros of h^2+5h=155 are h=(-5+sqrt(645))/2 ,h=(-5-sqrt(645))/2

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h^{2} + 5 h = 155

h = \frac{- 5 + 645}{2}, h = \frac{- 5 - 645}{2}

Decimal Notation

h = 10.19842 \dots, h = - 15.19842 \dots

Solution steps

h^{2} + 5 h = 155

Move

155

to the left side

h^{2} + 5 h - 155 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 155 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 155) = 645

h_{1, 2} = \frac{- 5 \pm 645}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 5 + 645}{2 \cdot 1}, h_{2} = \frac{- 5 - 645}{2 \cdot 1}

h = \frac{- 5 + 645}{2 \cdot 1} : \frac{- 5 + 645}{2}

h = \frac{- 5 - 645}{2 \cdot 1} : \frac{- 5 - 645}{2}

The solutions to the quadratic equation are:

h = \frac{- 5 + 645}{2}, h = \frac{- 5 - 645}{2}

h^{2} - 7 h = 0

y, z = y^{2} + \frac{x ^{3}}{3} + x y

(20 + 2 x) (10 + 2 x) = 200 + 64

(50 t)^{2} + (60 t)^{2} = 30 0^{2}

11 c^{2} + 27 c + 14 = 2 c^{2}

What are the solutions to the equation h^2+5h=155 ?
The solutions to the equation h^2+5h=155 are h=(-5+sqrt(645))/2 ,h=(-5-sqrt(645))/2
Find the zeros of h^2+5h=155
The zeros of h^2+5h=155 are h=(-5+sqrt(645))/2 ,h=(-5-sqrt(645))/2