What are the solutions to the equation (20+2x)(10+2x)=200+64 ?

The solutions to the equation (20+2x)(10+2x)=200+64 are x=1,x=-16

Find the zeros of (20+2x)(10+2x)=200+64

The zeros of (20+2x)(10+2x)=200+64 are x=1,x=-16

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(20 + 2 x) (10 + 2 x) = 200 + 64

x = 1, x = - 16

Solution steps

(20 + 2 x) (10 + 2 x) = 200 + 64

Expand

(20 + 2 x) (10 + 2 x) : 200 + 60 x + 4 x^{2}

200 + 60 x + 4 x^{2} = 264

Move

264

to the left side

4 x^{2} + 60 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 4 ( - 64 )}{2 \cdot 4}

6 0^{2} - 4 \cdot 4 (- 64) = 68

x_{1, 2} = \frac{- 60 \pm 68}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 60 + 68}{2 \cdot 4}, x_{2} = \frac{- 60 - 68}{2 \cdot 4}

x = \frac{- 60 + 68}{2 \cdot 4} : 1

x = \frac{- 60 - 68}{2 \cdot 4} : - 16

The solutions to the quadratic equation are:

x = 1, x = - 16

(50 t)^{2} + (60 t)^{2} = 30 0^{2}

11 c^{2} + 27 c + 14 = 2 c^{2}

5 x^{2} + 10 x - 2 = 0

x, 36 x^{2} - 36 x + 36 y^{2} + 24 y + 13 = 0

2 - 3 x - 2 x^{2} = 0

What are the solutions to the equation (20+2x)(10+2x)=200+64 ?
The solutions to the equation (20+2x)(10+2x)=200+64 are x=1,x=-16
Find the zeros of (20+2x)(10+2x)=200+64
The zeros of (20+2x)(10+2x)=200+64 are x=1,x=-16