What are the solutions to the equation solvefor x,3x^2+4x-1=0 ?

The solutions to the equation solvefor x,3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

Find the zeros of solvefor x,3x^2+4x-1=0

The zeros of solvefor x,3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

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x, 3 x^{2} + 4 x - 1 = 0

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

Decimal Notation

x = 0.21525 \dots, x = - 1.54858 \dots

Solution steps

3 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 1) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 3}

x = \frac{- 4 + 2 7}{2 \cdot 3} : \frac{- 2 + 7}{3}

x = \frac{- 4 - 2 7}{2 \cdot 3} : - \frac{2 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

7 x^{2} - 6 x + 5 = - 4

36 x^{2} = 9

18 x^{2} + 50 = 0

x^{2} = 23 + 2 x

x, 8 x^{2} + 4 y^{2} + 2 z^{2} - 24 = 0

What are the solutions to the equation solvefor x,3x^2+4x-1=0 ?
The solutions to the equation solvefor x,3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3
Find the zeros of solvefor x,3x^2+4x-1=0
The zeros of solvefor x,3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3