What are the solutions to the equation x^2=23+2x ?

The solutions to the equation x^2=23+2x are x=1+2sqrt(6),x=1-2sqrt(6)

Find the zeros of x^2=23+2x

The zeros of x^2=23+2x are x=1+2sqrt(6),x=1-2sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 23 + 2 x

x = 1 + 26, x = 1 - 26

Decimal Notation

x = 5.89897 \dots, x = - 3.89897 \dots

Solution steps

x^{2} = 23 + 2 x

Move

2 x

to the left side

x^{2} - 2 x = 23

Move

23

to the left side

x^{2} - 2 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 23) = 46

x_{1, 2} = \frac{- ( - 2 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 6}{2 \cdot 1} : 1 + 26

x = \frac{- ( - 2 ) - 4 6}{2 \cdot 1} : 1 - 26

The solutions to the quadratic equation are:

x = 1 + 26, x = 1 - 26

x, 8 x^{2} + 4 y^{2} + 2 z^{2} - 24 = 0

(4 - x)^{2} = 100

p^{2} + 4 p + 3 = 0

3 x^{2} - 24 x = 48

5 x^{2} + 5 x - 1 = - x^{2} + 4 x

What are the solutions to the equation x^2=23+2x ?
The solutions to the equation x^2=23+2x are x=1+2sqrt(6),x=1-2sqrt(6)
Find the zeros of x^2=23+2x
The zeros of x^2=23+2x are x=1+2sqrt(6),x=1-2sqrt(6)