What are the solutions to the equation 3x^2-24x=48 ?

The solutions to the equation 3x^2-24x=48 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

Find the zeros of 3x^2-24x=48

The zeros of 3x^2-24x=48 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

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3 x^{2} - 24 x = 48

x = 4 (1 + 2), x = 4 (1 - 2)

Decimal Notation

x = 9.65685 \dots, x = - 1.65685 \dots

Solution steps

3 x^{2} - 24 x = 48

Move

48

to the left side

3 x^{2} - 24 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 ( - 48 )}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 (- 48) = 242

x_{1, 2} = \frac{- ( - 24 ) \pm 24 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 24 2}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 24 2}{2 \cdot 3}

x = \frac{- ( - 24 ) + 24 2}{2 \cdot 3} : 4 (1 + 2)

x = \frac{- ( - 24 ) - 24 2}{2 \cdot 3} : 4 (1 - 2)

The solutions to the quadratic equation are:

x = 4 (1 + 2), x = 4 (1 - 2)

5 x^{2} + 5 x - 1 = - x^{2} + 4 x

x^{2} + x + 1 = 3

(k + d - b)^{2} = a

2 x^{2} - 1 = 1

(x + 6)^{2} - 2 = 5

What are the solutions to the equation 3x^2-24x=48 ?
The solutions to the equation 3x^2-24x=48 are x=4(1+sqrt(2)),x=4(1-sqrt(2))
Find the zeros of 3x^2-24x=48
The zeros of 3x^2-24x=48 are x=4(1+sqrt(2)),x=4(1-sqrt(2))