What are the solutions to the equation (x+6)(x-6)-8=1-4x ?

The solutions to the equation (x+6)(x-6)-8=1-4x are x=5,x=-9

Find the zeros of (x+6)(x-6)-8=1-4x

The zeros of (x+6)(x-6)-8=1-4x are x=5,x=-9

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(x + 6) (x - 6) - 8 = 1 - 4 x

x = 5, x = - 9

Solution steps

(x + 6) (x - 6) - 8 = 1 - 4 x

Expand

(x + 6) (x - 6) - 8 : x^{2} - 44

x^{2} - 44 = 1 - 4 x

Move

4 x

to the left side

x^{2} - 44 + 4 x = 1

Move

1

to the left side

x^{2} + 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 14}{2 \cdot 1}

x = \frac{- 4 + 14}{2 \cdot 1} : 5

x = \frac{- 4 - 14}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

0 = 3 x^{2} + 8 x + 4

3 x^{2} + 8 x = 2 x - 9

s^{2} = 4

21 = (x + 3)^{2} - 4

x^{2} + 16 x = 22

What are the solutions to the equation (x+6)(x-6)-8=1-4x ?
The solutions to the equation (x+6)(x-6)-8=1-4x are x=5,x=-9
Find the zeros of (x+6)(x-6)-8=1-4x
The zeros of (x+6)(x-6)-8=1-4x are x=5,x=-9