What are the solutions to the equation 3x^2+8x=2x-9 ?

The solutions to the equation 3x^2+8x=2x-9 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of 3x^2+8x=2x-9

The zeros of 3x^2+8x=2x-9 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

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3 x^{2} + 8 x = 2 x - 9

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

3 x^{2} + 8 x = 2 x - 9

Move

9

to the left side

3 x^{2} + 8 x + 9 = 2 x

Move

2 x

to the left side

3 x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 9 : 62 i

x_{1, 2} = \frac{- 6 \pm 6 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 2 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 2 i}{2 \cdot 3}

x = \frac{- 6 + 6 2 i}{2 \cdot 3} : - 1 + 2 i

x = \frac{- 6 - 6 2 i}{2 \cdot 3} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

s^{2} = 4

21 = (x + 3)^{2} - 4

x^{2} + 16 x = 22

x^{2} - 5 x + c = 0

(1 - x) (2 - x) = 0

What are the solutions to the equation 3x^2+8x=2x-9 ?
The solutions to the equation 3x^2+8x=2x-9 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of 3x^2+8x=2x-9
The zeros of 3x^2+8x=2x-9 are x=-1+sqrt(2)i,x=-1-sqrt(2)i