What are the solutions to the equation (1-x)(2-x)=0 ?

The solutions to the equation (1-x)(2-x)=0 are x=1,x=2

Find the zeros of (1-x)(2-x)=0

The zeros of (1-x)(2-x)=0 are x=1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - x) (2 - x) = 0

x = 1, x = 2

Solution steps

(1 - x) (2 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 - x = 0 or 2 - x = 0

Solve

1 - x = 0 : x = 1

Solve

2 - x = 0 : x = 2

The solutions to the quadratic equation are:

x = 1, x = 2

4 y^{2} - 1.6 y + 0.1225 = 0

f, 2 f + x (f)^{2} = 10

9^{2} = (62)^{2} + r^{2}

a, \frac{a ^{2} - b ^{2}}{9} = a + b

3 x^{2} + \frac{4 ( 3 x + 1 )}{3} = 0

What are the solutions to the equation (1-x)(2-x)=0 ?
The solutions to the equation (1-x)(2-x)=0 are x=1,x=2
Find the zeros of (1-x)(2-x)=0
The zeros of (1-x)(2-x)=0 are x=1,x=2