What are the solutions to the equation 9^2=(6sqrt(2))^2+r^2 ?

The solutions to the equation 9^2=(6sqrt(2))^2+r^2 are r=3,r=-3

Find the zeros of 9^2=(6sqrt(2))^2+r^2

The zeros of 9^2=(6sqrt(2))^2+r^2 are r=3,r=-3

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9^{2} = (62)^{2} + r^{2}

r = 3, r = - 3

Solution steps

9^{2} = (62)^{2} + r^{2}

Expand

9^{2} : 81

Expand

(62)^{2} + r^{2} : 72 + r^{2}

81 = 72 + r^{2}

Switch sides

72 + r^{2} = 81

Move

72

to the right side

r^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 9, r = - 9

9 = 3

- 9 = - 3

r = 3, r = - 3

a, \frac{a ^{2} - b ^{2}}{9} = a + b

3 x^{2} + \frac{4 ( 3 x + 1 )}{3} = 0

5 n^{2} - 6 n - 27 = 0

x^{2} - a^{2} - b x - ab = 0

(x + 4) (x - 2) = 8

What are the solutions to the equation 9^2=(6sqrt(2))^2+r^2 ?
The solutions to the equation 9^2=(6sqrt(2))^2+r^2 are r=3,r=-3
Find the zeros of 9^2=(6sqrt(2))^2+r^2
The zeros of 9^2=(6sqrt(2))^2+r^2 are r=3,r=-3