What are the solutions to the equation a^2=2ax-x^2 ?

The solutions to the equation a^2=2ax-x^2 are x=a

Find the zeros of a^2=2ax-x^2

The zeros of a^2=2ax-x^2 are x=a

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a^{2} = 2 a x - x^{2}

x = a

Solution steps

a^{2} = 2 a x - x^{2}

Switch sides

2 a x - x^{2} = a^{2}

Move

a^{2}

to the left side

2 a x - x^{2} - a^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 a x - a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 a \pm ( 2 a ) ^{2} - 4 ( - 1 ) ( - a ^{2} )}{2 ( - 1 )}

(2 a)^{2} - 4 (- 1) (- a^{2}) = 0

x_{1, 2} = \frac{- 2 a \pm 0}{2 ( - 1 )}

x = \frac{- 2 a}{2 ( - 1 )}

Simplify

\frac{- 2 a}{2 ( - 1 )} : a

x = a

The solution to the quadratic equation is:

x = a

9 n^{2} - 5 = - 99

n^{2} = 1

4 u^{2} + 9 = - 12 u

3 k^{2} + k - 1 = 0

(4 - 2 y)^{2} + 4 y^{2} = 16

What are the solutions to the equation a^2=2ax-x^2 ?
The solutions to the equation a^2=2ax-x^2 are x=a
Find the zeros of a^2=2ax-x^2
The zeros of a^2=2ax-x^2 are x=a