What are the solutions to the equation (x+2)^2=3x+7 ?

The solutions to the equation (x+2)^2=3x+7 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

Find the zeros of (x+2)^2=3x+7

The zeros of (x+2)^2=3x+7 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

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(x + 2)^{2} = 3 x + 7

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Decimal Notation

x = 1.30277 \dots, x = - 2.30277 \dots

Solution steps

(x + 2)^{2} = 3 x + 7

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

x^{2} + 4 x + 4 = 3 x + 7

Move

7

to the left side

x^{2} + 4 x - 3 = 3 x

Move

3 x

to the left side

x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 3) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 1}, x_{2} = \frac{- 1 - 13}{2 \cdot 1}

x = \frac{- 1 + 13}{2 \cdot 1} : \frac{- 1 + 13}{2}

x = \frac{- 1 - 13}{2 \cdot 1} : \frac{- 1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

(x - 3) (x - 2) = 20

6 - 7 x = 3 x^{2}

n^{2} + 19 n + 66 = 6

w, m w^{2} = \frac{9 k \pm 41 k}{4}

0.9 \cdot 0.85 \cdot 210 \cdot 10 \cdot x \cdot (17 - 0.5 \cdot x) = 0.88 \cdot 1 0^{5}

What are the solutions to the equation (x+2)^2=3x+7 ?
The solutions to the equation (x+2)^2=3x+7 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2
Find the zeros of (x+2)^2=3x+7
The zeros of (x+2)^2=3x+7 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2