What are the solutions to the equation z^2-2z+3=0 ?

The solutions to the equation z^2-2z+3=0 are z=1+sqrt(2)i,z=1-sqrt(2)i

Find the zeros of z^2-2z+3=0

The zeros of z^2-2z+3=0 are z=1+sqrt(2)i,z=1-sqrt(2)i

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z^{2} - 2 z + 3 = 0

z = 1 + 2 i, z = 1 - 2 i

Solution steps

z^{2} - 2 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

z_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, z_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

z = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

z = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

z = 1 + 2 i, z = 1 - 2 i

- x^{2} - 6 = 0

3 (x + 11)^{2} - 12 = 0

0 = 3 x^{2} - 18 x + 24

3 s^{2} + 2 s + 1 = 0

4 x^{2} - 12 x - (x + 5)^{2} = - 32

What are the solutions to the equation z^2-2z+3=0 ?
The solutions to the equation z^2-2z+3=0 are z=1+sqrt(2)i,z=1-sqrt(2)i
Find the zeros of z^2-2z+3=0
The zeros of z^2-2z+3=0 are z=1+sqrt(2)i,z=1-sqrt(2)i