What are the solutions to the equation 3(x+11)^2-12=0 ?

The solutions to the equation 3(x+11)^2-12=0 are x=-9,x=-13

Find the zeros of 3(x+11)^2-12=0

The zeros of 3(x+11)^2-12=0 are x=-9,x=-13

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3 (x + 11)^{2} - 12 = 0

x = - 9, x = - 13

Solution steps

3 (x + 11)^{2} - 12 = 0

Move

12

to the right side

3 (x + 11)^{2} = 12

Divide both sides by

3

(x + 11)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 11 = 4 : x = - 9

Solve

x + 11 = - 4 : x = - 13

The solutions to the quadratic equation are:

x = - 9, x = - 13

0 = 3 x^{2} - 18 x + 24

3 s^{2} + 2 s + 1 = 0

4 x^{2} - 12 x - (x + 5)^{2} = - 32

25 - 2 x^{2} = 0

(x + 1)^{2} - 3 = 0

What are the solutions to the equation 3(x+11)^2-12=0 ?
The solutions to the equation 3(x+11)^2-12=0 are x=-9,x=-13
Find the zeros of 3(x+11)^2-12=0
The zeros of 3(x+11)^2-12=0 are x=-9,x=-13