What are the solutions to the equation (x+1)^2-3=0 ?

The solutions to the equation (x+1)^2-3=0 are x=sqrt(3)-1,x=-sqrt(3)-1

Find the zeros of (x+1)^2-3=0

The zeros of (x+1)^2-3=0 are x=sqrt(3)-1,x=-sqrt(3)-1

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(x + 1)^{2} - 3 = 0

x = 3 - 1, x = - 3 - 1

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

(x + 1)^{2} - 3 = 0

Move

3

to the right side

(x + 1)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 3 : x = 3 - 1

Solve

x + 1 = - 3 : x = - 3 - 1

The solutions to the quadratic equation are:

x = 3 - 1, x = - 3 - 1

x^{2} - 200 x + 9600 = 0

x^{2} + 10 x + c

a^{2} - 6 a - 40 = 0

1.2 x^{2} + 4 x - 8 = 0

x, 2 x^{2} + 2 y^{2} - 4 x + 4 y + 19 = 0

What are the solutions to the equation (x+1)^2-3=0 ?
The solutions to the equation (x+1)^2-3=0 are x=sqrt(3)-1,x=-sqrt(3)-1
Find the zeros of (x+1)^2-3=0
The zeros of (x+1)^2-3=0 are x=sqrt(3)-1,x=-sqrt(3)-1