What are the solutions to the equation x^2-200x+9600=0 ?

The solutions to the equation x^2-200x+9600=0 are x=120,x=80

Find the zeros of x^2-200x+9600=0

The zeros of x^2-200x+9600=0 are x=120,x=80

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x^{2} - 200 x + 9600 = 0

x = 120, x = 80

Solution steps

x^{2} - 200 x + 9600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 1 \cdot 9600}{2 \cdot 1}

(- 200)^{2} - 4 \cdot 1 \cdot 9600 = 40

x_{1, 2} = \frac{- ( - 200 ) \pm 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 40}{2 \cdot 1}, x_{2} = \frac{- ( - 200 ) - 40}{2 \cdot 1}

x = \frac{- ( - 200 ) + 40}{2 \cdot 1} : 120

x = \frac{- ( - 200 ) - 40}{2 \cdot 1} : 80

The solutions to the quadratic equation are:

x = 120, x = 80

x^{2} + 10 x + c

a^{2} - 6 a - 40 = 0

1.2 x^{2} + 4 x - 8 = 0

x, 2 x^{2} + 2 y^{2} - 4 x + 4 y + 19 = 0

3 y^{2} = 12 y^{2} - 144

What are the solutions to the equation x^2-200x+9600=0 ?
The solutions to the equation x^2-200x+9600=0 are x=120,x=80
Find the zeros of x^2-200x+9600=0
The zeros of x^2-200x+9600=0 are x=120,x=80