What are the solutions to the equation 1.2x^2+4x-8=0 ?

The solutions to the equation 1.2x^2+4x-8=0 are x=(-5+sqrt(85))/3 ,x=-(5+sqrt(85))/3

Find the zeros of 1.2x^2+4x-8=0

The zeros of 1.2x^2+4x-8=0 are x=(-5+sqrt(85))/3 ,x=-(5+sqrt(85))/3

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1.2 x^{2} + 4 x - 8 = 0

x = \frac{- 5 + 85}{3}, x = - \frac{5 + 85}{3}

Decimal Notation

x = 1.40651 \dots, x = - 4.73984 \dots

Solution steps

1.2 x^{2} + 4 x - 8 = 0

Multiply both sides by

10

12 x^{2} + 40 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 12 ( - 80 )}{2 \cdot 12}

4 0^{2} - 4 \cdot 12 (- 80) = 885

x_{1, 2} = \frac{- 40 \pm 8 85}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 40 + 8 85}{2 \cdot 12}, x_{2} = \frac{- 40 - 8 85}{2 \cdot 12}

x = \frac{- 40 + 8 85}{2 \cdot 12} : \frac{- 5 + 85}{3}

x = \frac{- 40 - 8 85}{2 \cdot 12} : - \frac{5 + 85}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 85}{3}, x = - \frac{5 + 85}{3}

x, 2 x^{2} + 2 y^{2} - 4 x + 4 y + 19 = 0

3 y^{2} = 12 y^{2} - 144

9 x^{2} - 63 = 0

x (7 x - 5) = 0

x (2 x - 7) - 4 x + 14 = 0

What are the solutions to the equation 1.2x^2+4x-8=0 ?
The solutions to the equation 1.2x^2+4x-8=0 are x=(-5+sqrt(85))/3 ,x=-(5+sqrt(85))/3
Find the zeros of 1.2x^2+4x-8=0
The zeros of 1.2x^2+4x-8=0 are x=(-5+sqrt(85))/3 ,x=-(5+sqrt(85))/3