What are the solutions to the equation -4x^2-19x+5=0 ?

The solutions to the equation -4x^2-19x+5=0 are x=-5,x= 1/4

Find the zeros of -4x^2-19x+5=0

The zeros of -4x^2-19x+5=0 are x=-5,x= 1/4

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- 4 x^{2} - 19 x + 5 = 0

x = - 5, x = \frac{1}{4}

Decimal

x = - 5, x = 0.25

Solution steps

- 4 x^{2} - 19 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

(- 19)^{2} - 4 (- 4) \cdot 5 = 21

x_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 21}{2 ( - 4 )}, x_{2} = \frac{- ( - 19 ) - 21}{2 ( - 4 )}

x = \frac{- ( - 19 ) + 21}{2 ( - 4 )} : - 5

x = \frac{- ( - 19 ) - 21}{2 ( - 4 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = - 5, x = \frac{1}{4}

y^{2} - 4 y - 45 = 0

3 x^{2} + 9 x + 7 = 0

3 x^{2} = 27 x

\frac{2}{3} x^{2} + 20 = 2

6 x^{2} - 1 x - 2 = 0

What are the solutions to the equation -4x^2-19x+5=0 ?
The solutions to the equation -4x^2-19x+5=0 are x=-5,x= 1/4
Find the zeros of -4x^2-19x+5=0
The zeros of -4x^2-19x+5=0 are x=-5,x= 1/4