What are the solutions to the equation 2/3 x^2+20=2 ?

The solutions to the equation 2/3 x^2+20=2 are x=3sqrt(3)i,x=-3sqrt(3)i

Find the zeros of 2/3 x^2+20=2

The zeros of 2/3 x^2+20=2 are x=3sqrt(3)i,x=-3sqrt(3)i

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\frac{2}{3} x^{2} + 20 = 2

x = 33 i, x = - 33 i

Solution steps

\frac{2}{3} x^{2} + 20 = 2

Move

20

to the right side

\frac{2}{3} x^{2} = - 18

Multiply both sides by

3

2 x^{2} = - 54

Divide both sides by

2

x^{2} = - 27

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 27, x = - - 27

- 27 = 33 i

- - 27 = - 33 i

x = 33 i, x = - 33 i

6 x^{2} - 1 x - 2 = 0

(D + \frac{2}{25}) x^{1} - \frac{1}{50} x^{2} = 0

x^{2} - 6 x - 11

x^{2} - 6 x - 16

- 0.002 x^{2} + 0.37 x = 8

What are the solutions to the equation 2/3 x^2+20=2 ?
The solutions to the equation 2/3 x^2+20=2 are x=3sqrt(3)i,x=-3sqrt(3)i
Find the zeros of 2/3 x^2+20=2
The zeros of 2/3 x^2+20=2 are x=3sqrt(3)i,x=-3sqrt(3)i