What are the solutions to the equation b^2+2b+43=0 ?

The solutions to the equation b^2+2b+43=0 are b=-1+sqrt(42)i,b=-1-sqrt(42)i

Find the zeros of b^2+2b+43=0

The zeros of b^2+2b+43=0 are b=-1+sqrt(42)i,b=-1-sqrt(42)i

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b^{2} + 2 b + 43 = 0

b = - 1 + 42 i, b = - 1 - 42 i

Solution steps

b^{2} + 2 b + 43 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 43}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 43 : 242 i

b_{1, 2} = \frac{- 2 \pm 2 42 i}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 2 + 2 42 i}{2 \cdot 1}, b_{2} = \frac{- 2 - 2 42 i}{2 \cdot 1}

b = \frac{- 2 + 2 42 i}{2 \cdot 1} : - 1 + 42 i

b = \frac{- 2 - 2 42 i}{2 \cdot 1} : - 1 - 42 i

The solutions to the quadratic equation are:

b = - 1 + 42 i, b = - 1 - 42 i

x, x^{2} = 3 x + 10

3 x^{2} - 8 x - 21 = 0

9 - 3 x^{2} + 5 x - 8 + 7 x^{2} = 5 x^{2} - 9 + 4 x + 4 x

405 - 168 x + 12 x^{2} = 0

0 = x^{2} - 6 x - 16

What are the solutions to the equation b^2+2b+43=0 ?
The solutions to the equation b^2+2b+43=0 are b=-1+sqrt(42)i,b=-1-sqrt(42)i
Find the zeros of b^2+2b+43=0
The zeros of b^2+2b+43=0 are b=-1+sqrt(42)i,b=-1-sqrt(42)i