What are the solutions to the equation 4(x-6)^2=48 ?

The solutions to the equation 4(x-6)^2=48 are x=2sqrt(3)+6,x=-2sqrt(3)+6

Find the zeros of 4(x-6)^2=48

The zeros of 4(x-6)^2=48 are x=2sqrt(3)+6,x=-2sqrt(3)+6

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4 (x - 6)^{2} = 48

x = 23 + 6, x = - 23 + 6

Decimal Notation

x = 9.46410 \dots, x = 2.53589 \dots

Solution steps

4 (x - 6)^{2} = 48

Divide both sides by

4

(x - 6)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = 12 : x = 23 + 6

Solve

x - 6 = - 12 : x = - 23 + 6

The solutions to the quadratic equation are:

x = 23 + 6, x = - 23 + 6

0 = x^{2} - 2 x - 7

- 4 x^{2} + 6 x + 4 = 0

2 x (x + 1) - 4 (x + 4) = 8

9 x^{2} - 256 = 0

a^{2} + 1 5^{2} = 2 5^{2}

What are the solutions to the equation 4(x-6)^2=48 ?
The solutions to the equation 4(x-6)^2=48 are x=2sqrt(3)+6,x=-2sqrt(3)+6
Find the zeros of 4(x-6)^2=48
The zeros of 4(x-6)^2=48 are x=2sqrt(3)+6,x=-2sqrt(3)+6