What are the solutions to the equation -4x^2+6x+4=0 ?

The solutions to the equation -4x^2+6x+4=0 are x=-1/2 ,x=2

Find the zeros of -4x^2+6x+4=0

The zeros of -4x^2+6x+4=0 are x=-1/2 ,x=2

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- 4 x^{2} + 6 x + 4 = 0

x = - \frac{1}{2}, x = 2

Decimal Notation

x = - 0.5, x = 2

Solution steps

- 4 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

6^{2} - 4 (- 4) \cdot 4 = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 ( - 4 )}, x_{2} = \frac{- 6 - 10}{2 ( - 4 )}

x = \frac{- 6 + 10}{2 ( - 4 )} : - \frac{1}{2}

x = \frac{- 6 - 10}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 2

2 x (x + 1) - 4 (x + 4) = 8

9 x^{2} - 256 = 0

a^{2} + 1 5^{2} = 2 5^{2}

x, 2 x^{2} + 5 x + 2 = 0

3 x^{2} + 2 = - 62

What are the solutions to the equation -4x^2+6x+4=0 ?
The solutions to the equation -4x^2+6x+4=0 are x=-1/2 ,x=2
Find the zeros of -4x^2+6x+4=0
The zeros of -4x^2+6x+4=0 are x=-1/2 ,x=2