What are the solutions to the equation 3x^2+16x=0 ?

The solutions to the equation 3x^2+16x=0 are x=0,x=-16/3

Find the zeros of 3x^2+16x=0

The zeros of 3x^2+16x=0 are x=0,x=-16/3

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3 x^{2} + 16 x = 0

x = 0, x = - \frac{16}{3}

Decimal Notation

x = 0, x = - 5.33333 \dots

Solution steps

3 x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 \cdot 3}, x_{2} = \frac{- 16 - 16}{2 \cdot 3}

x = \frac{- 16 + 16}{2 \cdot 3} : 0

x = \frac{- 16 - 16}{2 \cdot 3} : - \frac{16}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{16}{3}

2 m^{2} + 13 m + 20 = 0

2 x^{2} - \frac{1}{2} = 0

- 4 x^{2} + 6 x - 16 = - 5 x^{2}

x^{2} - 10 x + 27

x^{2} - 10 x + 18

What are the solutions to the equation 3x^2+16x=0 ?
The solutions to the equation 3x^2+16x=0 are x=0,x=-16/3
Find the zeros of 3x^2+16x=0
The zeros of 3x^2+16x=0 are x=0,x=-16/3