What are the solutions to the equation q^2+4q-5=0 ?

The solutions to the equation q^2+4q-5=0 are q=1,q=-5

Find the zeros of q^2+4q-5=0

The zeros of q^2+4q-5=0 are q=1,q=-5

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q^{2} + 4 q - 5 = 0

q = 1, q = - 5

Solution steps

q^{2} + 4 q - 5 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

q_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 4 + 6}{2 \cdot 1}, q_{2} = \frac{- 4 - 6}{2 \cdot 1}

q = \frac{- 4 + 6}{2 \cdot 1} : 1

q = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

q = 1, q = - 5

x, x^{2} + 4 x y + 16 y^{2} = 27

16 x^{2} - 4 x + 5 = 0

(x - 5)^{2} - 80 = 0

(x + 6)^{2} = - 4

2 x^{2} + 12 x + 13

What are the solutions to the equation q^2+4q-5=0 ?
The solutions to the equation q^2+4q-5=0 are q=1,q=-5
Find the zeros of q^2+4q-5=0
The zeros of q^2+4q-5=0 are q=1,q=-5