What are the solutions to the equation 16x^2-4x+5=0 ?

The solutions to the equation 16x^2-4x+5=0 are x= 1/8+i(sqrt(19))/8 ,x= 1/8-i(sqrt(19))/8

Find the zeros of 16x^2-4x+5=0

The zeros of 16x^2-4x+5=0 are x= 1/8+i(sqrt(19))/8 ,x= 1/8-i(sqrt(19))/8

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16 x^{2} - 4 x + 5 = 0

x = \frac{1}{8} + i \frac{19}{8}, x = \frac{1}{8} - i \frac{19}{8}

Solution steps

16 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

Simplify

(- 4)^{2} - 4 \cdot 16 \cdot 5 : 419 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 19 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 19 i}{2 \cdot 16}, x_{2} = \frac{- ( - 4 ) - 4 19 i}{2 \cdot 16}

x = \frac{- ( - 4 ) + 4 19 i}{2 \cdot 16} : \frac{1}{8} + i \frac{19}{8}

x = \frac{- ( - 4 ) - 4 19 i}{2 \cdot 16} : \frac{1}{8} - i \frac{19}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{19}{8}, x = \frac{1}{8} - i \frac{19}{8}

(x - 5)^{2} - 80 = 0

(x + 6)^{2} = - 4

2 x^{2} + 12 x + 13

x^{2} = - 7 x + 170

2 x^{2} - x + 15 = 0

What are the solutions to the equation 16x^2-4x+5=0 ?
The solutions to the equation 16x^2-4x+5=0 are x= 1/8+i(sqrt(19))/8 ,x= 1/8-i(sqrt(19))/8
Find the zeros of 16x^2-4x+5=0
The zeros of 16x^2-4x+5=0 are x= 1/8+i(sqrt(19))/8 ,x= 1/8-i(sqrt(19))/8