What are the solutions to the equation x^2=-7x+170 ?

The solutions to the equation x^2=-7x+170 are x=10,x=-17

Find the zeros of x^2=-7x+170

The zeros of x^2=-7x+170 are x=10,x=-17

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x^{2} = - 7 x + 170

x = 10, x = - 17

Solution steps

x^{2} = - 7 x + 170

Move

170

to the left side

x^{2} - 170 = - 7 x

Move

7 x

to the left side

x^{2} - 170 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 170 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 170 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 170) = 27

x_{1, 2} = \frac{- 7 \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 27}{2 \cdot 1}, x_{2} = \frac{- 7 - 27}{2 \cdot 1}

x = \frac{- 7 + 27}{2 \cdot 1} : 10

x = \frac{- 7 - 27}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 10, x = - 17

2 x^{2} - x + 15 = 0

8^{2} + 3^{2} = x^{2}

y^{2} + 2 y = 8

- 3 x^{2} - 15 x + 2250 = 0

2 q^{2} + 14 q - 5 = 0

What are the solutions to the equation x^2=-7x+170 ?
The solutions to the equation x^2=-7x+170 are x=10,x=-17
Find the zeros of x^2=-7x+170
The zeros of x^2=-7x+170 are x=10,x=-17