What are the solutions to the equation ax^2=bx ?

The solutions to the equation ax^2=bx are x=0,x= b/a ;\quad a\ne 0

Find the zeros of ax^2=bx

The zeros of ax^2=bx are x=0,x= b/a ;\quad a\ne 0

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a x^{2} = b x

x = 0, x = \frac{b}{a}; a \neq = 0

Solution steps

a x^{2} = b x

Move

b x

to the left side

a x^{2} - b x = 0

Factor

a x^{2} - b x : x (a x - b)

x (a x - b) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or a x - b = 0

Solve

a x - b = 0 : x = \frac{b}{a}; a \neq = 0

The solutions to the quadratic equation are:

x = 0, x = \frac{b}{a}; a \neq = 0

y^{2} = 4 - 3 y^{2}

x (x + 7) = 1 + 7 x

x^{2} + 16 = - 12 x

4 x^{2} - 6 x - 18 = 0

a^{2} + 8 a = 0

What are the solutions to the equation ax^2=bx ?
The solutions to the equation ax^2=bx are x=0,x= b/a ;\quad a\ne 0
Find the zeros of ax^2=bx
The zeros of ax^2=bx are x=0,x= b/a ;\quad a\ne 0