What are the solutions to the equation -3x^2+4x=-8 ?

The solutions to the equation -3x^2+4x=-8 are x=-(2(sqrt(7)-1))/3 ,x=(2(1+sqrt(7)))/3

Find the zeros of -3x^2+4x=-8

The zeros of -3x^2+4x=-8 are x=-(2(sqrt(7)-1))/3 ,x=(2(1+sqrt(7)))/3

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- 3 x^{2} + 4 x = - 8

x = - \frac{2 ( 7 - 1 )}{3}, x = \frac{2 ( 1 + 7 )}{3}

Decimal Notation

x = - 1.09716 \dots, x = 2.43050 \dots

Solution steps

- 3 x^{2} + 4 x = - 8

Move

8

to the left side

- 3 x^{2} + 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

4^{2} - 4 (- 3) \cdot 8 = 47

x_{1, 2} = \frac{- 4 \pm 4 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 7}{2 ( - 3 )}, x_{2} = \frac{- 4 - 4 7}{2 ( - 3 )}

x = \frac{- 4 + 4 7}{2 ( - 3 )} : - \frac{2 ( 7 - 1 )}{3}

x = \frac{- 4 - 4 7}{2 ( - 3 )} : \frac{2 ( 1 + 7 )}{3}

The solutions to the quadratic equation are:

x = - \frac{2 ( 7 - 1 )}{3}, x = \frac{2 ( 1 + 7 )}{3}

20 = y^{2}

40 = (x + 20) (x - 20)

0 = - 3 x^{2}

9 - x^{2} - x - 3 = 0

2 x^{2} - 7 x = 3

What are the solutions to the equation -3x^2+4x=-8 ?
The solutions to the equation -3x^2+4x=-8 are x=-(2(sqrt(7)-1))/3 ,x=(2(1+sqrt(7)))/3
Find the zeros of -3x^2+4x=-8
The zeros of -3x^2+4x=-8 are x=-(2(sqrt(7)-1))/3 ,x=(2(1+sqrt(7)))/3