What are the solutions to the equation completesquare x^2+4x+8=0 ?

The solutions to the equation completesquare x^2+4x+8=0 are x=2i-2,x=-2i-2

Find the zeros of completesquare x^2+4x+8=0

The zeros of completesquare x^2+4x+8=0 are x=2i-2,x=-2i-2

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x^{2} + 4 x + 8 = 0

x = 2 i - 2, x = - 2 i - 2

Solution steps

x^{2} + 4 x + 8 = 0

Move

8

to the right side

x^{2} + 4 x = - 8

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = - 4

For

the solutions are

f (x) = a, - a

Solve

x + 2 = - 4 : x = 2 i - 2

Solve

x + 2 = - - 4 : x = - 2 i - 2

The solutions to the quadratic equation are:

x = 2 i - 2, x = - 2 i - 2

3 x^{2} - 48 x + 144 = 0

2 x^{2} - 4 x = 0

x^{2} + 12 x + c

x^{2} - \frac{15}{2} x + \frac{45}{4} = 0

6 x^{2} - 18 x - 108 = 0

What are the solutions to the equation completesquare x^2+4x+8=0 ?
The solutions to the equation completesquare x^2+4x+8=0 are x=2i-2,x=-2i-2
Find the zeros of completesquare x^2+4x+8=0
The zeros of completesquare x^2+4x+8=0 are x=2i-2,x=-2i-2