What are the solutions to the equation m^2-6m+25=0 ?

The solutions to the equation m^2-6m+25=0 are m=3+4i,m=3-4i

Find the zeros of m^2-6m+25=0

The zeros of m^2-6m+25=0 are m=3+4i,m=3-4i

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m^{2} - 6 m + 25 = 0

m = 3 + 4 i, m = 3 - 4 i

Solution steps

m^{2} - 6 m + 25 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

m_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, m_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

m = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

m = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

m = 3 + 4 i, m = 3 - 4 i

- x (x + 2) + 3 = 0

2 x^{2} - 20 x - 22 = 0

12 x^{2} - 116 x + 190 = 0

0 = - x^{2} + 2 x - 1

x^{2} + (\frac{a}{a + b} + \frac{a + b}{a}) x + 1 = 0

What are the solutions to the equation m^2-6m+25=0 ?
The solutions to the equation m^2-6m+25=0 are m=3+4i,m=3-4i
Find the zeros of m^2-6m+25=0
The zeros of m^2-6m+25=0 are m=3+4i,m=3-4i