What are the solutions to the equation 8x^2-192x=0 ?

The solutions to the equation 8x^2-192x=0 are x=24,x=0

Find the zeros of 8x^2-192x=0

The zeros of 8x^2-192x=0 are x=24,x=0

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8 x^{2} - 192 x = 0

x = 24, x = 0

Solution steps

8 x^{2} - 192 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 192 ) \pm ( - 192 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 192)^{2} - 4 \cdot 8 \cdot 0 = 192

x_{1, 2} = \frac{- ( - 192 ) \pm 192}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 192 ) + 192}{2 \cdot 8}, x_{2} = \frac{- ( - 192 ) - 192}{2 \cdot 8}

x = \frac{- ( - 192 ) + 192}{2 \cdot 8} : 24

x = \frac{- ( - 192 ) - 192}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = 24, x = 0

2 x^{2} + 26 = 0

x^{2} + 12 x - 10 = - 4

2 x^{2} - 12 x - 7 = 0

x, x y^{2} - x^{2} + 1 = 0

16 y^{2} = 81

What are the solutions to the equation 8x^2-192x=0 ?
The solutions to the equation 8x^2-192x=0 are x=24,x=0
Find the zeros of 8x^2-192x=0
The zeros of 8x^2-192x=0 are x=24,x=0