What are the solutions to the equation 2x^2-12x-7=0 ?

The solutions to the equation 2x^2-12x-7=0 are x=(6+5sqrt(2))/2 ,x=(6-5sqrt(2))/2

Find the zeros of 2x^2-12x-7=0

The zeros of 2x^2-12x-7=0 are x=(6+5sqrt(2))/2 ,x=(6-5sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 12 x - 7 = 0

x = \frac{6 + 5 2}{2}, x = \frac{6 - 5 2}{2}

Decimal Notation

x = 6.53553 \dots, x = - 0.53553 \dots

Solution steps

2 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 7) = 102

x_{1, 2} = \frac{- ( - 12 ) \pm 10 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10 2}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 10 2}{2 \cdot 2}

x = \frac{- ( - 12 ) + 10 2}{2 \cdot 2} : \frac{6 + 5 2}{2}

x = \frac{- ( - 12 ) - 10 2}{2 \cdot 2} : \frac{6 - 5 2}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 5 2}{2}, x = \frac{6 - 5 2}{2}

x, x y^{2} - x^{2} + 1 = 0

16 y^{2} = 81

2 x^{2} - 12 x - 8 = 0

a^{2} - 5 = 0

x, (x - 3)^{2} + (y + 6)^{2} = 0

What are the solutions to the equation 2x^2-12x-7=0 ?
The solutions to the equation 2x^2-12x-7=0 are x=(6+5sqrt(2))/2 ,x=(6-5sqrt(2))/2
Find the zeros of 2x^2-12x-7=0
The zeros of 2x^2-12x-7=0 are x=(6+5sqrt(2))/2 ,x=(6-5sqrt(2))/2