What are the solutions to the equation 12x^2+x=63 ?

The solutions to the equation 12x^2+x=63 are x= 9/4 ,x=-7/3

Find the zeros of 12x^2+x=63

The zeros of 12x^2+x=63 are x= 9/4 ,x=-7/3

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12 x^{2} + x = 63

x = \frac{9}{4}, x = - \frac{7}{3}

Decimal Notation

x = 2.25, x = - 2.33333 \dots

Solution steps

12 x^{2} + x = 63

Move

63

to the left side

12 x^{2} + x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 12 ( - 63 )}{2 \cdot 12}

1^{2} - 4 \cdot 12 (- 63) = 55

x_{1, 2} = \frac{- 1 \pm 55}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 1 + 55}{2 \cdot 12}, x_{2} = \frac{- 1 - 55}{2 \cdot 12}

x = \frac{- 1 + 55}{2 \cdot 12} : \frac{9}{4}

x = \frac{- 1 - 55}{2 \cdot 12} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - \frac{7}{3}

4 x - x^{2} = x + 1

m^{2} - \frac{49}{2} m = \frac{1}{2}

a, y = (a x + b)^{2}

1 2^{2} + b^{2} = 3 7^{2}

12 + 1.6 x = 8 x - \frac{1}{5} x^{2}

What are the solutions to the equation 12x^2+x=63 ?
The solutions to the equation 12x^2+x=63 are x= 9/4 ,x=-7/3
Find the zeros of 12x^2+x=63
The zeros of 12x^2+x=63 are x= 9/4 ,x=-7/3