What are the solutions to the equation 2(x+1)^2=32 ?

The solutions to the equation 2(x+1)^2=32 are x=3,x=-5

Find the zeros of 2(x+1)^2=32

The zeros of 2(x+1)^2=32 are x=3,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x + 1)^{2} = 32

x = 3, x = - 5

Solution steps

2 (x + 1)^{2} = 32

Divide both sides by

2

(x + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 16 : x = 3

Solve

x + 1 = - 16 : x = - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

y^{2} - 2 y - 11 = 0

2 x^{2} + 30 = 0

16 (4 x - 1)^{2} = 25

x^{2} - 18 x + 82

x, x^{2} y^{2} + 2 x - 6 = 0

What are the solutions to the equation 2(x+1)^2=32 ?
The solutions to the equation 2(x+1)^2=32 are x=3,x=-5
Find the zeros of 2(x+1)^2=32
The zeros of 2(x+1)^2=32 are x=3,x=-5