What are the solutions to the equation 16(4x-1)^2=25 ?

The solutions to the equation 16(4x-1)^2=25 are x= 9/16 ,x=-1/16

Find the zeros of 16(4x-1)^2=25

The zeros of 16(4x-1)^2=25 are x= 9/16 ,x=-1/16

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16 (4 x - 1)^{2} = 25

x = \frac{9}{16}, x = - \frac{1}{16}

Decimal

x = 0.5625, x = - 0.0625

Solution steps

16 (4 x - 1)^{2} = 25

Divide both sides by

16

(4 x - 1)^{2} = \frac{25}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = \frac{25}{16} : x = \frac{9}{16}

Solve

4 x - 1 = - \frac{25}{16} : x = - \frac{1}{16}

The solutions to the quadratic equation are:

x = \frac{9}{16}, x = - \frac{1}{16}

x^{2} - 18 x + 82

x, x^{2} y^{2} + 2 x - 6 = 0

6 x^{2} - x + 6 = 0

3 x^{2} - 48 x + 180 = 0

42 x^{2} - 36 x + 6 = 0

What are the solutions to the equation 16(4x-1)^2=25 ?
The solutions to the equation 16(4x-1)^2=25 are x= 9/16 ,x=-1/16
Find the zeros of 16(4x-1)^2=25
The zeros of 16(4x-1)^2=25 are x= 9/16 ,x=-1/16