What are the solutions to the equation (3x-1)^2-13=-9 ?

The solutions to the equation (3x-1)^2-13=-9 are x=1,x=-1/3

Find the zeros of (3x-1)^2-13=-9

The zeros of (3x-1)^2-13=-9 are x=1,x=-1/3

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(3 x - 1)^{2} - 13 = - 9

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

(3 x - 1)^{2} - 13 = - 9

Move

13

to the right side

(3 x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 4 : x = 1

Solve

3 x - 1 = - 4 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

3 x^{2} + 7 x + 14 = - 7 x

2 x = (x + 2) (x - 1)

6 x^{2} + 31 x + 35 = 0

(a + 3) (a - 5) = 5

x^{2} = 1 + x - x^{2}

What are the solutions to the equation (3x-1)^2-13=-9 ?
The solutions to the equation (3x-1)^2-13=-9 are x=1,x=-1/3
Find the zeros of (3x-1)^2-13=-9
The zeros of (3x-1)^2-13=-9 are x=1,x=-1/3